added gfx
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@@ -115,7 +115,7 @@ In the following a simple and inexpensive approach for receiving this informatio
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By writing
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\begin{equation}
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p(\vec{q}_{t+1} \mid \vec{q}_t, \mObsVec_t)_{\text{step}} = \mathcal{N}(\Delta d_t \mid \mu_{\text{step}}, \sigma_{\gDist}^2)
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p(\vec{q}_{t+1} \mid \vec{q}_t, \mObsVec_t)_{\text{step}} = \mathcal{N}(\Delta d_t \mid \mu_{\text{step}}, \sigma_{\text{step}}^2)
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\label{eq:smoothingTransDistance}
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\end{equation}
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we receive a statement about how likely it is to cover a distance $\Delta d_t$ between two states $\vec{q}_{t+1}$ and $\vec{q}_{t}$.
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@@ -123,8 +123,8 @@ In the easiest case, $\Delta d_t$ is the linear distance between two states.
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Of course, based on the graph structure, one could calculate the shortest path between both and sum up the respective edge lengths.
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However, this requires tremendous calculation time for negligible improvements.
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Therefore this is not further discussed within this work.
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The average step length $\mu_{\text{step}}$ is based on the pedestrian's walking speed and $\sigma_{\gDist}^2$ denotes the step length's variance.
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Both values are chosen depending on the activity $x$ recognized at time $t$.
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The average step length $\mu_{\text{step}}$ is based on the pedestrian's walking speed and $\sigma_{\text{step}}^2$ denotes the step length's variance.
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Both values are chosen depending on the activity $\mObsActivity$ recognized at time $t$.
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For example $\mu_{\text{step}}$ gets smaller while a pedestrian is walking upstairs, than just walking straight.
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This requires to extend the smoothing transition by the current observation $\mObsVec_t$.
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Since $\mStateVec$ is hidden and the Markov property is satisfied, we are able to do so.
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