tex fixes

This commit is contained in:
2016-02-29 12:13:00 +01:00
parent 6ef06459cb
commit 020cbc5d94

View File

@@ -271,24 +271,25 @@
% %
As new states $\mStateVec_{t}$ should approach the pedestrian's destination As new states $\mStateVec_{t}$ should approach the pedestrian's destination
we use a reference $\pathRef$ all states try to reach. This references must we use a reference $\pathRef$ all states try to reach. This references must
be both part of the shortest path and located somewhere outside of the sample-set. be a) part of the shortest path and b) located somewhere outside of the sample-set.
% %
We thus calculate the standard deviation of the distance of all sample-positions For b) we need to know the current position distribution and therefore calculate
$\fPos{\mStateVec_{t-1}}$ from aforementioned centre $\pathCentroid$. the standard deviation of the distance of all sample-positions $\fPos{\mStateVec_{t-1}}$
from aforementioned centre $\pathCentroid$.
%\commentByFrank{so klarer? platz fuer groese Eq. fehlt und Notation zum ansprechen jedes einzelnen Particles vermeide ich lieber...} %\commentByFrank{so klarer? platz fuer groese Eq. fehlt und Notation zum ansprechen jedes einzelnen Particles vermeide ich lieber...}
% %
%\begin{equation} %\begin{equation}
% d_\text{cen} = \| pos(q_{t-1}) - \pathCentroid \| % d_\text{cen} = \| pos(q_{t-1}) - \pathCentroid \|
% \sigma_\text{cen} = stdDev(distance) % \sigma_\text{cen} = stdDev(distance)
%\end{equation} %\end{equation}
%
After advancing the starting-vertex by three times this deviation After advancing the starting-vertex by three times this deviation
we get the new point $\pathRef$ that is: part of the shortest path, outside of the sample-set we get the new point $\pathRef$ that is: part of the shortest path, outside of the sample-set
and closer (but not too close) to the desired destination. and closer (but not too close) to the desired destination.
%
Hereafter, the simple transition \refeq{eq:transSimple} is combined with a second probability, Hereafter, the simple transition \refeq{eq:transSimple} is combined with a second probability,
downvoting all grid-steps that depart from $\pathRef$. downvoting all grid-steps that depart from $\pathRef$.
To still allow leaving the shortest path, the intensity of the downvoting is controlled via $\mUsePath$, To still allow leaving the shortest path, the intensity of downvoting is controlled via $\mUsePath$,
with $0 < \mUsePath < 1$. with $0 < \mUsePath < 1$.
Finally, \refeq{eq:transShortestPath} provides a metric tending towards the reference while Finally, \refeq{eq:transShortestPath} provides a metric tending towards the reference while
still allowing the pedestrian to leave the shortest path: still allowing the pedestrian to leave the shortest path:
@@ -335,7 +336,9 @@
\end{equation} \end{equation}
% %
Fig. \ref{fig:multiHeatMap} shows a heat-map of how often vertices were visited after several Fig. \ref{fig:multiHeatMap} shows a heat-map of how often vertices were visited after several
\SI{125}{\meter} walks. The colours from cold to hot indicate that both possible paths random walks from $\mVertexA$ towards $\mVertexDest$.
%\SI{125}{\meter} walks.
The colours from cold to hot indicate that both possible paths
are covered and slight deviations from the shortest version are possible. are covered and slight deviations from the shortest version are possible.
% %
\begin{figure} \begin{figure}
@@ -348,7 +351,7 @@
%\commentByFrank{so besser?} %\commentByFrank{so besser?}
\label{fig:multiHeatMap} \label{fig:multiHeatMap}
\end{figure} \end{figure}
%
It should be noted that the normal distribution in \eqref{eq:transShortestPath} and \eqref{eq:transMultiPath} does not integrate to \SI{1}{} due to circularity of angular data. It should be noted that the normal distribution in \eqref{eq:transShortestPath} and \eqref{eq:transMultiPath} does not integrate to \SI{1}{} due to circularity of angular data.
This normally requires wrapped distributions like the von Mises distribution. This normally requires wrapped distributions like the von Mises distribution.
However, in our case, the normal distribution can be assumed as sufficient for small enough $\sigma^2$. However, in our case, the normal distribution can be assumed as sufficient for small enough $\sigma^2$.